@adarshmohanty where are you located that they are still using aluminum wiring? There are so many issues with aluminum wiring due to the expansion and contraction of the aluminum during peak power usage. There are also issues with heat, resistance and corrosion if it gets connected to copper terminals.
From your question, it looks like your household voltage is in the 220V range. W/220V=23A (22.7) Now add a safety factor of 1.25 to it and you get 29A (28.75). So your wire needs to have an ampacity of around 30A.
For my area of the world, that would mean I would need a #10AWG wire. That (in copper) has a cross section of 5.26mm so that would be a 6mm for your purpose. Your 8 sq mm falls between a 10AWG and an 8AWG from here
It'll work but I'd go bigger if available.
This "Is this still because of the aluminium cable or is it normal to get low voltage around this time since its peak summer time now" we really can't answer. We do not know what your power company supplies. I would imagine that they are having difficulty supplying sufficient power to the population during peak season.
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Brian - did you say Rabbit Hole? I’m all the way in!
Here’s a chart showing the coefficient of thermal expansion of various metals (in laymen’s terms that means how much it expands when it gets hot - I remembered just enough from Physics class to find this):
Aluminum rates at 21-24, Copper is 16-16.7 (I’m not sure what the units are but it’s probably not important for our purposes). Basically, aluminum moves a lot more than copper. Hence, its problems with wiring since it will work its way loose at connection points as it heats/cools.
What I’m trying to wrap my head around is if/why larger gauge wires aren’t as affected? I’m thinking it has something to do with the way cross-sectional area is calculated and the amount of material inside the circle. A loose analogy I would give is flow rates through pipes. The squaring in the formula makes the area get exponentially larger as the radius gets larger and I’m thinking (maybe?) that keeps the outside of the conductor from moving as much (%-wise) as the aluminum conductor gets larger.
My sister teaches college Physics so this is right up her alley… I’ll try to remember to ask her next time I talk to her if no one here knows for sure if my suspicion is accurate.
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